ICSE Class 10 Matrices — Mock Test (2027)
Free online mock test for Matrices (ICSE Class 10 Mathematics) — 20 competency-based questions based on the latest CISCE 2027 syllabus, with instant marking. Try the samples below, then take the full test free.
What to expect: This mock test covers key concepts from the Matrices chapter — including application-based and competency-focused questions aligned with how ICSE actually sets the paper.
Tip: Attempt without notes first to identify gaps, then review explanations for any wrong answers. Retake after a few days for best retention.
Sample questions
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1.If $A = \begin{bmatrix} 4 & -4 \\ -3 & 3 \end{bmatrix}$, $B = \begin{bmatrix} 6 & 5 \\ 3 & 0 \end{bmatrix}$, and $C = \begin{bmatrix} 2 & 3 \\ -1 & -2 \end{bmatrix}$, it is found that $AB = AC$. Which of the following conclusions can be drawn from this result?
- A.Matrix multiplication follows the cancellation law, so $B = C$.
- B.The cancellation law does not apply to matrix multiplication, so $B$ and $C$ may differ.
- C.Matrix $A$ must be singular because $AB = AC$ but $B \neq C$.
- D.The result $AB = AC$ implies that $B$ and $C$ are inverses of each other.
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2.Find the values of $x$ and $y$ that satisfy the equation: $$\begin{bmatrix} 3 & -2 \\ -1 & 4 \end{bmatrix} \begin{bmatrix} 2x \\ 1 \end{bmatrix} + 2 \begin{bmatrix} -4 \\ 5 \end{bmatrix} = 4 \begin{bmatrix} 2 \\ y \end{bmatrix}$$
- A.$x = 2$, $y = 3$
- B.$x = 1$, $y = 4$
- C.$x = 3$, $y = 2$
- D.$x = -2$, $y = 1$
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3.Let $A = \begin{bmatrix} 1 & -1 \ 2 & 3 \ \end{bmatrix}$ and $B = \begin{bmatrix} 4 & 1 \ 2 & 0 \ \end{bmatrix}$. Find the matrix $C$ such that $A + 2C = B$.
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4.For the equation $\begin{bmatrix} -2 & 0 \\ 3 & 1 \end{bmatrix} \begin{bmatrix} -1 \\ 2x \end{bmatrix} + 3 \begin{bmatrix} -2 \\ 1 \end{bmatrix} = 2 \begin{bmatrix} y \\ 3 \end{bmatrix}$, what are the values of $x$ and $y$?
- A.x = 3 and y = -2
- B.x = -3 and y = 2
- C.x = 2 and y = -3
- D.x = -2 and y = 3
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5.Find the value of $x$, $y$, $u$ and $v$, when: $\left[ \begin{array}{cc} x + 2y & u - 2v \\ x - 2y & 2u + v \end{array} \right] = \left[ \begin{array}{cc} 11 & 8 \\ 3 & 6 \end{array} \right]$
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