ICSE Class 10 Linear Inequations (in one variable) — Mock Test (2027)
Free online mock test for Linear Inequations (in one variable) (ICSE Class 10 Mathematics) — 20 competency-based questions based on the latest CISCE 2027 syllabus, with instant marking. Try the samples below, then take the full test free.
What to expect: This mock test covers key concepts from the Linear Inequations (in one variable) chapter — including application-based and competency-focused questions aligned with how ICSE actually sets the paper.
Tip: Attempt without notes first to identify gaps, then review explanations for any wrong answers. Retake after a few days for best retention.
Sample questions
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1.Find the set of values of x satisfying both inequations below, where x ∈ N, and select the correct solution set: 5x - 3 ≤ 9x + 5 and 5 - (4/7)x ≥ (1/7)x - 5/7.
- A.{1, 2, 3, 4, 5}
- B.{0, 1, 2, 3, 4, 5, 6}
- C.{2, 3, 4, 5, 6}
- D.{1, 2, 3, 4, 5, 6}
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2.Solve the inequation: $2x + \frac{7}{2} > \frac{5x}{3} + 3$ and represent the solution on the number line.
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3.Ravi obtained 70 and 75 marks in first two unit tests. Then, the minimum marks he should get in the third test to have an average of at least 60 marks, are:
- A.45
- B.35
- C.25
- D.None of these
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4.The solution set of the inequation: $x - 3 \geq -5, x \in R$ is:
- A.$[x : x > -2, x \in R]$
- B.$[x : x \leq -2, x \in R]$
- C.$[x : x \geq -2, x \in R]$
- D.$[-2, -1, 0, 1, 2]$
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5.Multiplying $-3$ on both sides of a linear inequation $\frac{-2x + 7}{3} \leq \frac{-4x + 5}{3}$ becomes
- A.$-2x + 7 \geq -4x + 5$
- B.$2x - 7 \geq 4x - 5$
- C.$-2x + 7 \leq 4x - 5$
- D.$2x - 7 \leq 4x - 5$
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